10-29c+10c^2=0

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Solution for 10-29c+10c^2=0 equation:


Simplifying
10 + -29c + 10c2 = 0

Solving
10 + -29c + 10c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(2 + -5c)(5 + -2c) = 0

Subproblem 1

Set the factor '(2 + -5c)' equal to zero and attempt to solve: Simplifying 2 + -5c = 0 Solving 2 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5c = 0 + -2 -5c = 0 + -2 Combine like terms: 0 + -2 = -2 -5c = -2 Divide each side by '-5'. c = 0.4 Simplifying c = 0.4

Subproblem 2

Set the factor '(5 + -2c)' equal to zero and attempt to solve: Simplifying 5 + -2c = 0 Solving 5 + -2c = 0 Move all terms containing c to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -2c = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -2c = 0 + -5 -2c = 0 + -5 Combine like terms: 0 + -5 = -5 -2c = -5 Divide each side by '-2'. c = 2.5 Simplifying c = 2.5

Solution

c = {0.4, 2.5}

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